03/10/2016

03/10/2016: More on Mesh Current

I. Introduction:

We continued where we left with on Tuesday, which was about Mesh Current.

Here we were asked to solve the circuit using Mesh analysis. We took a look of the inner meshes, which were 3 of them. We set up the equations to solve the 3 unknowns

i1, i2, and i3 are respectively -2.57A, -.342A, and 0.428A

II. Compared the node voltage method with Mesh analysis

There would be some situations where meshes produce less equations compared to the nodal analysis; therefore, easier to solve. However, nodal would be more powerful for parallel circuit.

Another example of three meshes, three equations and three unknowns, our goal is to find the voltage across the 6.8kOhm

While Sam was setting the circuit, I was doing the every circuit to make sure that our work was correct, which it was

II. Experiment:
1. Experiment 1:
Here we were given 4 resistors as shown below. Our goal was to verify that our pre-lab calculation was correct using Analog Discovery

Here were our recorded values for each of the resistors, with color code next to it

The voltage is 5v, and current is 0.332mA, which matched up with our pre-lab values

Here was the close view of the set up

Here was our data

The difference of error is 3 percent, which was in the acceptable range 

Here is a close view of diode ,which is a semiconductor allowing the flow of current in one direction only

III. BJT Tracer:

We already had Beta, which was about 50, we solved for IB=165 micro A. Then we plugged it back to solve V_o

Using the lab manual, we set up the scale for graph we were going to collect

A close view of the circuit with the 2N304 transistor

IV. Conclusion;

Today, we kept going with the mesh analysis. We spent some of our time setting up the circuit and test for many parts, such as the voltage and current across a specific resistor. We learned the concept of the diode- which was a semi-conductor. And transistor, which collects the current and gives a greater output